“Joao Fonseca punishes Andriy Rublev at the 2025 Australian Open”, — write: sport.ua
In the 1st round of the major, the winner of the ATP Youth Final Tournament 2024 defeated the “neutral” Andrei Rublev (ATP 9) in three sets in 2 hours and 26 minutes.
Australian Open 2025. 1/64 of the final
Joao Fonseca (Brazil) [Q] – Andrei Rublev [9] – 7:6 (7:1), 6:3, 7:6 (7:5)
This was the first meeting of the rivals. Fonseca gave only one serve for the match and made two breaks.
In his first Grand Slam tournament, Joao started with qualification. In the selection, he won against Agustin Gomez, Colman Wong and Thiago Tirante.
Fonseca’s win streak is now 14 matches. In addition to Next Gen ATP Finals (5 wins) and AO qualification, Fonseca also won the challenger trophy in Canberra at the start of 2025.
Fonseca played his second match against a top-20 player and won his second. In Jeddah at the Youth Final, he shut out Arthur Fies, who was then ranked 20th.
Fonseca’s next opponent at the Australian Open will be Lorenzo Sonego (Italy, ATP 55), who passed Stan Wawrinka (Switzerland, WTA 156) at the start of the major.
In 2025, Rublev played two matches and lost both. In addition, his streak is 5 matches – he played another 3 games at the Final Tournament 2024.
— #AusOpen (@AustralianOpen) January 14, 2025
