Ukrainian defender Oleksandr Zinchenko will sign a six-month contract with Amsterdam Ajax, during which he will earn 2.5 million euros. This is reported by FootballTransfers.
In the Amsterdam club, Zinchenko will be the highest paid player. His closest competitors Ko Itakura and Kasper Dolberg earn €3.53m per year (€1.765m per half year).
“Ajax” will pay London “Arsenal” 3.5-4 million euros for the transfer of the Ukrainian defender. It is noted that in the summer the parties will be able to discuss the terms of a possible extension of cooperation.
It was reported that Zinchenko agreed to the terms of the contract with Ajax.
Source: sport.ua